Problem 38

Pandigital multiples

Take the number 192 and multiply it by each of 1, 2, and 3:

192 1 = 192

192 2 = 384

192 3 = 576

By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)

The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).

What is the largest 1 to 9 pandigital 9-digit number that can be
formed as the concatenated product of an integer with (1,2, ... , `n`) where `n` 1?

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